DSE Passpaper_Basic Circle_Ratio 型

☆    MC  2013  DSE  19  [ C ]     56%  ( YouTube )

 In the figure, ABCD is a circle. AC and BD intersect at E. If AB = AD and AD // BC, then ÐBAE =

        A.    53^o.

        B.    57^o.

        C.    69^o.

        D.    74^o.

☆    MC  2015  DSE  20  [ C ]  60%  ( YouTube )

 In the figure, AD is a diameter of the circle ABCDE. If ÐBAD = 58° and BC = CD, then ÐAEC =

        A.    32°.

        B.    58°.

        C.    61°.

        D.    64°.

☆    MC  2017  DSE  21 [ C ]  59%  ( YouTube )

In the figure, AD is a diameter of the circle ABCDE. If BC = CD and ÐABC = 110°, then ÐBED =

        A.    20°.

        B.    35°.

        C.    40°.

        D.    55°.

☆    MC  2018  DSE  39  [ B ]  28%   ( YouTube )

In the figure, TA is the tangent to the circle ABCD at the point A. CD produced and TA produced meet at the point E. It is given that AB = CD, ÐBAT = 24° and ÐAED = 72°. Find ÐABC.

        A.    60°

        B.    66°

        C.    72°

        D.    78°

☆    MC  2019  DSE  21  [ B ]  53%  ( YouTube )

In the figure, O is the centre of the semi-circle ABCD. If AC = BD and ÐCOD = 48°, then ÐABD =

        A.    31°.

        B.    33°.

        C.    42°.

        D.    48°.

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